47x^2+1.617x-74.45=0

Solution for 47x^2+1.617x-74.45=0 equation:

47x^2+1.617x-74.45=0

a = 47; b = 1.617; c = -74.45;
Δ = b2-4ac
Δ = 1.6172-4·47·(-74.45)
Δ = 13999.214689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.617)-\sqrt{13999.214689}}{2*47}=\frac{-1.617-\sqrt{13999.214689}}{94}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.617)+\sqrt{13999.214689}}{2*47}=\frac{-1.617+\sqrt{13999.214689}}{94}
$